DataDisrupter

nuked from orbit

It's the only way to be sure.

I wasn't aware of that distinction about the energy for the laser to generate the heat energy within the reaction not being factored into the Q value, very interesting, thank you! Would that energy for the laser still be required in a "stable reaction" continuously, or would it be something that would "trail off"?

I didn't see any mention of the output in the article. 22MW injected, but does anyone know if the reaction was actually generating a positive output?

Parabéns!