this post was submitted on 07 Sep 2024
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[–] candyman337@sh.itjust.works 0 points 2 months ago (3 children)

No you can solve 3/4ths of your problems

[–] NegativeInf@lemmy.world 0 points 2 months ago (2 children)
[–] SnotFlickerman@lemmy.blahaj.zone 0 points 2 months ago (1 children)

Would that make Zeno's Wank just a type of edging?

[–] affiliate@lemmy.world 0 points 2 months ago

if you learn how to solve zeno’s problem in the first book, it may be possible to solve 100% of your problems in the second book

[–] 0x0@lemmy.dbzer0.com 0 points 2 months ago (1 children)

This all hinges on when you count the number of problems you have. But that's why you have two eyes! Read the same page of books 1 and 2 in parallel and obliterate 100% of your problems.

[–] stebo02@lemmy.dbzer0.com 0 points 2 months ago* (last edited 2 months ago)

I disagree. If one book solves half of your problems at random and the other does the same, that's still 75% on average, and 25% on average will have 2 solutions.

[–] Rusty@lemmy.ca 0 points 2 months ago (1 children)

If you buy 5 books, you'll be able to solve 96.88% of your problems.

[–] MentalEdge@sopuli.xyz 0 points 2 months ago (2 children)

Or you could just read the one book eight times for 99.6℅. Why buy more than one when one is enough to read as many times as you like?

[–] ulterno@lemmy.kde.social 0 points 2 months ago

Well guess what? That was an e-book and you only get to read once.

[–] bdot@lemmy.world 0 points 2 months ago

that’s some mighty fine fiscal responsibility, right there